FUNCIONES DE TRANSFERENCIA, VARIABLES DE ESTADO Y REDUCCIÓN DE DIAGRAMA DE BLOQUES

...

printsys(num1,den1,'s')

z1 =

2.5000

k1 =

7

p1 =

1.3300

0.5770

num1 =

0 7.0000 -17.5000

den1 =

1.0000 -1.9070 0.7674

num/den =

7 s - 17.5

-----------------------

s^2 - 1.907 s + 0.76741

%Problema2%

a=[1 0.21]; b=[1 0]; c=[1 6 30]; d=[1 -1]

num2=conv(a,b)

den2=conv(c,d)

printsys(num2,den2,'s')

d =

1 -1

num2 =

1.0000 0.2100 0

den2 =

1 5 24 -30

num/den =

s^2 + 0.21 s

-----------------------

s^3 + 5 s^2 + 24 s – 30

%Problema3%

e=[1 0.88]; f=[1 0.10]; p3=[0.42; 0.80; 0.99]; z2=[]; k2=[];

[num3,den3]=zp2tf(z2,p3,k2)

num3=conv(e,f)

printsys(num3,den3,'s')

num3 =

Empty matrix: 0-by-4

den3 =

1.0000 -2.2100 1.5438 -0.3326

num3 =

1.0000 0.9800 0.0880

num/den =

s^2 + 0.98 s + 0.088

-----------------------------------

s^3 - 2.21 s^2 + 1.5438 s - 0.33264

%Problema4%

g=[0 4]; h=[1 6]; hc=[1 4]; kg=[1 2];z4=[1; 3; 5]; p4=[]; k4=[1];

[num4,den4]=zp2tf(z4,p4,k4)

mm=conv(g,h);

le=conv(hc,kg);

den4=conv(mm,le)

printsys(num4,den4,'s')

num4 =

1 -9 23 -15

den4 =

1

den4 =

0 4 48 176 192

num/den =

s^3 - 9 s^2 + 23 s - 15

----------------------------

4 s^3 + 48 s^2 + 176 s + 192

%Problema5%

z1=[]

k1=1

p1=[2; 0.40]

[num5,den5]=zp2tf(z1,p1,k1)

printsys(num5,den5,'s')

z1 =

[]

k1 =

1

p1 =

2.0000

0.4000

num5 =

0 0 1

den5 =

1.0000 -2.4000 0.8000

num/den =

1

-----------------

s^2 - 2.4 s + 0.8

%Lab1%

%Asignación1%

%Parte4%

%Problema1%

num=[4 17 525];

den=[1 72 295 0 1600];

[z,p,k]=tf2zp(num,den)

z =

-2.1250 +11.2576i

-2.1250 -11.2576i

p =

-67.6331 + 0.0000i

-5.2813 + 0.0000i

0.4572 + 2.0665i

0.4572 - 2.0665i

k =

4

%Problema2%

num=[4 7];

den=[91 318 664];

[z,p,k]=tf2zp(num,den)

z =

-1.7500

p =

-1.7473 + 2.0601i

-1.7473 - 2.0601i

k =

0.0440

%Lab1%

%Asignación2%

%Problema2%

n1=[1 0.4 0.04];

d1=[1 0 0.01];

n2=[1];

d2=[1