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Las Leyes de Newton: estática y dinámica

Enviado por   •  25 de Octubre de 2018  •  883 Palabras (4 Páginas)  •  275 Visitas

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m1 = 105 g m2 = 125 g m3 =105 g

T1x = m1gcos T2x = m2gcos[pic 5][pic 6][pic 7][pic 8][pic 9][pic 10]

T1x = 1059.8cos 35 T2x = 1259.8cos 37[pic 11][pic 12][pic 13][pic 14]

T1x = 842,90N T2x = 978,32 N

T1y = m1gsen T2y = m2gsen T3y = m3g[pic 15][pic 16][pic 17][pic 18][pic 19][pic 20][pic 21]

T1y = 1059.8sen 35 T2y = 1259.8sen 37 T3y = 1059.8[pic 22][pic 23][pic 24][pic 25][pic 26]

T1y = 590,21 N T2y = 737,22 N T3y = 1.029 N

T2x - T1x = ? 978,32 – 842,90 = 135,42

T2y + T1y - T3y = ? 737,22 + 590,21 – 1.029 = 298,43

N°2

[pic 27][pic 28]

m1 = 125 g m2 = 145 g m3 =155 g

T1x = m1gcos T2x = m2gcos[pic 29][pic 30][pic 31][pic 32][pic 33][pic 34]

T1x = 1259.8cos 20 T2x = 1459.8cos 42[pic 35][pic 36][pic 37][pic 38]

T1x = 1.151,12 N T2x = 1.056 N

T1y = m1gsen T2y = m2gsen T3y = m3g[pic 39][pic 40][pic 41][pic 42][pic 43][pic 44][pic 45]

T1y = 1259.8sen 20 T2y = 1459.8sen 42 T3y = 1559.8[pic 46][pic 47][pic 48][pic 49][pic 50]

T1y = 418,97 N T2y = 950,83 N T3y = 1.519 N

T2x - T1x = ? 1.056 – 1.151,12 = - 95,12

T2y + T1y - T3y = ? 950,83 + 418,97 - 1.519 = - 149,2

N°3

[pic 51][pic 52]

m1 = 165 g m2 = 160 g m3 =135 g

T1x = m1gcos T2x = m2gcos[pic 53][pic 54][pic 55][pic 56][pic 57][pic 58]

T1x = 1659.8cos 44 T2x = 1609.8cos 24[pic 59][pic 60][pic 61][pic 62]

T1x = 1.163,17 N T2x = 1.432,43 N

T1y = m1gsen T2y = m2gsen T3y = m3g[pic 63][pic 64][pic 65][pic 66][pic 67][pic 68][pic 69]

T1y = 1659.8sen 44 T2y = 1609.8sen 24 T3y = 1359.8[pic 70][pic 71][pic 72][pic 73][pic 74]

T1y = 1.123,26 N T2y = 637,76 N T3y = 1.323 N

T2x - T1x =? 1.432,43 – 1.163,17 = 269,26

T2y + T1y - T3y =? 637,76 + 1.123,26 – 1.323 = 438,02

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