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3° Cuatrimestre Trabajo final

Enviado por   •  18 de Julio de 2018  •  656 Palabras (3 Páginas)  •  348 Visitas

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σ MAX= 2150MPA+2512.46 =396 MPA[pic 90]

[pic 91]

[pic 92]

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[pic 97][pic 98]

R= 2512.46σ MIN=-4662.46 MPA 396 MPA σ PROM= [pic 99][pic 100]

[pic 101][pic 102][pic 103]

σ X =-15 N/M2 σ Y= 18 N/M2 τ XY= 9 N/M2[pic 104][pic 105][pic 106][pic 107]

[pic 108]

[pic 109]

R=18.79[pic 110]

σ PROM= σ PROM= [pic 111][pic 112]

σ MIN= σ PROM – R [pic 113]

σ MIN= 16.5 N/M2 -18.79 = -2.29 N/M2[pic 114]

σ MAX= σ PROM + R[pic 115]

σ MAX= 16.5 N/M2 +18.79 =35.29 N/M2

[pic 116]

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[pic 122][pic 123]

R=18.79 σ MIN=-2.29 N/M235.29 N/M2 σ PROM= [pic 124][pic 125]

[pic 126][pic 127][pic 128]

[pic 129]

σ X =-750 N/M2 σ Y= 890 N/M2 τ XY= 590 N/M2[pic 130][pic 131][pic 132]

[pic 133]

[pic 134]

[pic 135]

R=1010.198[pic 136]

σ PROM= σ PROM= [pic 137][pic 138]

σ MIN= σ PROM – R [pic 139]

σ MIN= -820 N/M2-1010.198= -1830.198 N/M2[pic 140]

σ MAX= σ PROM + R

σ MAX= -820 N/M2+1010.198=190.198 N/M2[pic 141]

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R=1010.198 σ MIN=-1830.198 N/M2 σ PROM= [pic 150][pic 151]

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psi[pic 165]

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[pic 178][pic 179][pic 180]

4 en x [pic 181]

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esto es el mismo que el radio[pic 191][pic 192]

FLEXION

[pic 193][pic 194]

ΣFy = Ay-55N-75N+By=0

ΣFy= Ay-130N+By=0

ΣMo= -55N(2m)-75N(5m)+By(9m)

ΣMo= -110N/M-375N/M+By(9m)

ΣMo= 485N/M+By(9m)

By= = 53.88[pic 195]

Ay+By= 130N

Ay= 130N-By

Ay= 130N-53.88N

Ay= 76.12N

[pic 196]

26KN= 10KN[pic 197]

26KN=24KN[pic 198]

Σfy= 0[pic 199]

Ay-20KN-20KN-24KN+By=0

16KN-20KN-20KN-24KN+By=0

By= 48KN

ΣMB= 0

-Ay(15M)+20KN(9M)+20KN(3M)=0

15MAy= 180KN+60KN

Ay= [pic 200]

Ay= 16KN/M

[pic 201]

(15N/m)(7m)= 105N/m

ΣF= Ay-105N/m+By=0[pic 202]

Ay+By= 105N/m

ΣMo= (-105N/m)(3.5n)+By(7)=0

ΣMo=

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