3° Cuatrimestre Trabajo final
Enviado por John0099 • 18 de Julio de 2018 • 656 Palabras (3 Páginas) • 348 Visitas
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σ MAX= 2150MPA+2512.46 =396 MPA[pic 90]
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R= 2512.46σ MIN=-4662.46 MPA 396 MPA σ PROM= [pic 99][pic 100]
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σ X =-15 N/M2 σ Y= 18 N/M2 τ XY= 9 N/M2[pic 104][pic 105][pic 106][pic 107]
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R=18.79[pic 110]
σ PROM= σ PROM= [pic 111][pic 112]
σ MIN= σ PROM – R [pic 113]
σ MIN= 16.5 N/M2 -18.79 = -2.29 N/M2[pic 114]
σ MAX= σ PROM + R[pic 115]
σ MAX= 16.5 N/M2 +18.79 =35.29 N/M2
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R=18.79 σ MIN=-2.29 N/M235.29 N/M2 σ PROM= [pic 124][pic 125]
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σ X =-750 N/M2 σ Y= 890 N/M2 τ XY= 590 N/M2[pic 130][pic 131][pic 132]
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R=1010.198[pic 136]
σ PROM= σ PROM= [pic 137][pic 138]
σ MIN= σ PROM – R [pic 139]
σ MIN= -820 N/M2-1010.198= -1830.198 N/M2[pic 140]
σ MAX= σ PROM + R
σ MAX= -820 N/M2+1010.198=190.198 N/M2[pic 141]
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R=1010.198 σ MIN=-1830.198 N/M2 σ PROM= [pic 150][pic 151]
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psi[pic 165]
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4 en x [pic 181]
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esto es el mismo que el radio[pic 191][pic 192]
FLEXION
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ΣFy = Ay-55N-75N+By=0
ΣFy= Ay-130N+By=0
ΣMo= -55N(2m)-75N(5m)+By(9m)
ΣMo= -110N/M-375N/M+By(9m)
ΣMo= 485N/M+By(9m)
By= = 53.88[pic 195]
Ay+By= 130N
Ay= 130N-By
Ay= 130N-53.88N
Ay= 76.12N
[pic 196]
26KN= 10KN[pic 197]
26KN=24KN[pic 198]
Σfy= 0[pic 199]
Ay-20KN-20KN-24KN+By=0
16KN-20KN-20KN-24KN+By=0
By= 48KN
ΣMB= 0
-Ay(15M)+20KN(9M)+20KN(3M)=0
15MAy= 180KN+60KN
Ay= [pic 200]
Ay= 16KN/M
[pic 201]
(15N/m)(7m)= 105N/m
ΣF= Ay-105N/m+By=0[pic 202]
Ay+By= 105N/m
ΣMo= (-105N/m)(3.5n)+By(7)=0
ΣMo=
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