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Proyecto Informe Estatica

Enviado por   •  4 de Enero de 2019  •  1.300 Palabras (6 Páginas)  •  472 Visitas

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DE = -11,93 KN

DE = 11,93 KN © Tgβ = 2/2

Β = 45°

∑Fy = 0

6,67 – 4 – 8 + 11,93sen26,57 + JEsen45 = 0

JE = (-6,67 + 4 + 8 – 11,93sen26,57)/sen45

JE = -0,01 KN ©

∑Fx = 0

JI – 0,01cos45 – 11,93cos26,57 = 0

JI = 10,68 KN (T)

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[pic 21]

∑Mj = 0

5,33 x 6 + CDcos26,57 x 3 = 0 Tgα = 1/2

CD =(-5,33 X 6)/(Cos26,57 x 3) α = 26,57°

CD = -11,92 KN

CD = 11,92 KN © Tgβ = 2/2

Β = 45°

∑Fy = 0

5,33 – 8 + 11,92sen26,57 + JCsen45 = 0

JC = (-5,33 + 8 – 11,92Sen26,57)/Sen45

JC = -3,76 KN

JC = 3,76 KN ©

∑Fx = 0

-JK + 3,76Cos45 + 11,92Cos26,57 = 0

JK = (3,76Cos45 + 11,92Cos26,57)

JI = 13,32 KN (T)

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[pic 22][pic 23][pic 24][pic 25][pic 26]

∑MK = 0

5,33 x 8 – 8 x 2 + BCCos26,57 x 2 = 0 Tgα = 1/2

BC = (-5,33 x 8 + 8 x 2)/(Cos26,57 x 2) α = 26,57°

BC = -14,89 KN

BC = 14,89 KN © Tgβ = 2/2

Β = 45°

∑Fy = 0

5,33 – 8 – 4 + 14,89Sen26,57 + BKSen45= 0

BK = (-5,33 + 8 + 4 – 14,90Sen26,87)/Sen45

BK = 0,01 KN ©

∑Fx = 0

-KL – 0,01Cos45 + 14,89Cos26,57 = 0

KL = 13,31 KN (T)

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[pic 27][pic 28][pic 29][pic 30][pic 31]

∑MK = 0

-6,67 x 8 +4 x 4 + 8 x 2 – EFCos26,57 x 2 = 0 Tgα = 1/2

EF = (-6,67 X 8 + 4 X 4+ 8 X 2) α = 26,57°

EF = -11,94 KN

BC = 11,94 KN © Tgβ = 2/2

Β = 45°

∑Fy = 0

6,67 – 4 – 8 + 11,94Sen26,57 + IFSen45 = 0

IF = (-6,67 + 4 + 8 – 11,94Sen26,57)/(Sen45)

IF = -0,02 KN

IF = 0,02 KN ©

∑Fx = 0

-11,94Cos26,57 – 0,02Cos45 + IH = 0

IH = 11,04Cos26,57 + 0,02Cos45

IH = 10,69 KN (T)

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Nudo A

[pic 32]

∑Fy = 0

6,67 + ABSen26,57 = 0

AB = (-6,67)/Sen26,57

AB = -14,91

AB = 14,91 KN ©

∑Fx = 0

AL -14,91Cos 26,57

AL = 13,34 KN (T)

Nudo B

[pic 33]

∑Fy = 0

-BL + 0,01Sen45 – 14,91Sen26,57 + 14,89 Sen26,57 = 0

Bl = 0 KN

Nudo C

[pic 34]

∑Fy = 0

0,01Sen26,57 – CK = 0

CK = 0 KN

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Nudo D

[pic 35]

∑Fy = 0

-DJ + 11,92Sen26,57 + 11,93Sen26,57 = 0

Dj = 10,67 KN (T)

Nudo E

[pic 36]

∑Fy = 0

-EI + 11,94Sen26,57 + 0,01Sen45 + 11,93Sen26,57 = 0

EI = 10,68 KN (T)

Nudo F

[pic 37]

∑Fx = 0

-11,94Cos26,57 – 0,02Cos26,57 + FGCos26,57 = 0

Fg = (11,94Cos26,57 + 0,02Cos26,57)/(Cos26,57)

FG = 11,96 KN (T)

∑Fy = 0

-FH – 11,96Sen26,57 – 0,02Sen26,57 + 11,94Sen26,57 = 0

FH = - 0,02

FH = 0,02 KN ©

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