Proyecto Informe Estatica
Enviado por tolero • 4 de Enero de 2019 • 1.300 Palabras (6 Páginas) • 393 Visitas
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DE = -11,93 KN
DE = 11,93 KN © Tgβ = 2/2
Β = 45°
∑Fy = 0
6,67 – 4 – 8 + 11,93sen26,57 + JEsen45 = 0
JE = (-6,67 + 4 + 8 – 11,93sen26,57)/sen45
JE = -0,01 KN ©
∑Fx = 0
JI – 0,01cos45 – 11,93cos26,57 = 0
JI = 10,68 KN (T)
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[pic 21]
∑Mj = 0
5,33 x 6 + CDcos26,57 x 3 = 0 Tgα = 1/2
CD =(-5,33 X 6)/(Cos26,57 x 3) α = 26,57°
CD = -11,92 KN
CD = 11,92 KN © Tgβ = 2/2
Β = 45°
∑Fy = 0
5,33 – 8 + 11,92sen26,57 + JCsen45 = 0
JC = (-5,33 + 8 – 11,92Sen26,57)/Sen45
JC = -3,76 KN
JC = 3,76 KN ©
∑Fx = 0
-JK + 3,76Cos45 + 11,92Cos26,57 = 0
JK = (3,76Cos45 + 11,92Cos26,57)
JI = 13,32 KN (T)
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[pic 22][pic 23][pic 24][pic 25][pic 26]
∑MK = 0
5,33 x 8 – 8 x 2 + BCCos26,57 x 2 = 0 Tgα = 1/2
BC = (-5,33 x 8 + 8 x 2)/(Cos26,57 x 2) α = 26,57°
BC = -14,89 KN
BC = 14,89 KN © Tgβ = 2/2
Β = 45°
∑Fy = 0
5,33 – 8 – 4 + 14,89Sen26,57 + BKSen45= 0
BK = (-5,33 + 8 + 4 – 14,90Sen26,87)/Sen45
BK = 0,01 KN ©
∑Fx = 0
-KL – 0,01Cos45 + 14,89Cos26,57 = 0
KL = 13,31 KN (T)
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[pic 27][pic 28][pic 29][pic 30][pic 31]
∑MK = 0
-6,67 x 8 +4 x 4 + 8 x 2 – EFCos26,57 x 2 = 0 Tgα = 1/2
EF = (-6,67 X 8 + 4 X 4+ 8 X 2) α = 26,57°
EF = -11,94 KN
BC = 11,94 KN © Tgβ = 2/2
Β = 45°
∑Fy = 0
6,67 – 4 – 8 + 11,94Sen26,57 + IFSen45 = 0
IF = (-6,67 + 4 + 8 – 11,94Sen26,57)/(Sen45)
IF = -0,02 KN
IF = 0,02 KN ©
∑Fx = 0
-11,94Cos26,57 – 0,02Cos45 + IH = 0
IH = 11,04Cos26,57 + 0,02Cos45
IH = 10,69 KN (T)
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Nudo A
[pic 32]
∑Fy = 0
6,67 + ABSen26,57 = 0
AB = (-6,67)/Sen26,57
AB = -14,91
AB = 14,91 KN ©
∑Fx = 0
AL -14,91Cos 26,57
AL = 13,34 KN (T)
Nudo B
[pic 33]
∑Fy = 0
-BL + 0,01Sen45 – 14,91Sen26,57 + 14,89 Sen26,57 = 0
Bl = 0 KN
Nudo C
[pic 34]
∑Fy = 0
0,01Sen26,57 – CK = 0
CK = 0 KN
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Nudo D
[pic 35]
∑Fy = 0
-DJ + 11,92Sen26,57 + 11,93Sen26,57 = 0
Dj = 10,67 KN (T)
Nudo E
[pic 36]
∑Fy = 0
-EI + 11,94Sen26,57 + 0,01Sen45 + 11,93Sen26,57 = 0
EI = 10,68 KN (T)
Nudo F
[pic 37]
∑Fx = 0
-11,94Cos26,57 – 0,02Cos26,57 + FGCos26,57 = 0
Fg = (11,94Cos26,57 + 0,02Cos26,57)/(Cos26,57)
FG = 11,96 KN (T)
∑Fy = 0
-FH – 11,96Sen26,57 – 0,02Sen26,57 + 11,94Sen26,57 = 0
FH = - 0,02
FH = 0,02 KN ©
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