TEORIA DE ERRORES”

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Ves el volumen del cilindro en cada uno de los datos es la desviación estándar. Para calcular deben restar el promedio de los volúmenes menos cada uno de los volúmenes. se calcula elevando al cuadrado la desviación estándar es el error relativo se calcula dividiendo la entre el promedio se calcula multiplicando por 100 el ER

Volumen de un cilindro x³³

V = π x r² x h

V₁ = π x (88mm)² x 302mm x (100cm/1000mm)³ = 7347,21cm³²

V₂ = π x (90mm)² x 308mm x (100cm/1000mm)³ = 7837,65cm³

V₃ = π x (89mm)² x 298mm x (100cm/1000mm)³ = 7415,6cm³

V₄ = π x (90,5mm)² x 301mm x (100cm/1000mm)³ = 7744,86cm³

V₅ = π x (85,5mm)² x 290mm x (100cm/1000mm)³ = 6582,42cm³

V₆ = π x (89,5mm)² x 291,3mm x (100cm/1000mm)³ = 7330,55cm³

V₇ = π x (91,5mm)² x 297,5mm x (100cm/1000mm)³ = 7824,90cm³

Vprom = (7347,21+7837,65+7415,6+7744,86+6582,42+7330,55+7824,90)cm³/7 =7440,46cm³

∆Xi = Vprom – Vi

∆X₁ = (7440,46 - 7347,21)cm³ = 93,25cm³

∆X₂ = (7440,46 - 7837,65)cm³ = -397,19cm³

∆X₃ = (7440,46 - 7415,6)cm³ = 24,86cm³

∆X₄ = (7440,46 - 7744,86)cm³ = -304,4cm³

∆X₅ = (7440,46 - 6582,42)cm³ = 858,04cm³

∆X₆ = (7440,46 - 7330,55)cm³ = 109,91cm³

∆X₇ = (7440,46 – 7824,90)cm³ = -384,44cm³

∆X₁² = (93,25cm³)² = 8695,56cm⁶

∆X₂² = (-397,19cm³)² = 157759,9cm⁶

∆X₃² = (24,86cm³)² = 618,02cm⁶

∆X₄² = (-304,4cm³)² = 92659,36cm⁶

∆X₅² = (858,04cm³)² = 736232,64cm⁶

∆X₆² = (109,91cm³)² = 12080,21cm⁶

∆X₇² = (-384,44cm³)² = 147794,11cm⁶

ER = ∆Xi²/Vprom ER% = ER x 100

ER₁ = 8695,56cm⁶/ 7440,46cm³ = 1,16cm³ x 100 = 116%

ER₂ = 157759,9cm⁶/ 7440,46cm³ = 21,2cm³ x 100 = 2120%

ER₃ = 618,02cm⁶/ 7440,46cm³ = 0,08cm³ x 100 = 8%

ER₄ = 92659,36cm⁶/ 7440,46cm³ = 12,45cm³ x 100 = 1245%

ER₅ = 736232,64cm⁶/ 7440,46cm³ = 98,95cm³ x 100 = 9895%

ER₆ = 12080,21cm⁶/ 7440,46cm³ = 1,62cm³ x 100 = 162%

ER₇ = 147794,11cm⁶/ 7440,46cm³ = 19,86cm³ x 100 = 1986%