Ley de Boyle. Es una de las leyes de los gases ideales
Enviado por Mikki • 4 de Febrero de 2018 • 1.989 Palabras (8 Páginas) • 553 Visitas
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CÁLCULO PARA EL VOLUMEN
Ø = (7.7 ± 0.1) X 10-3 m
V = πø² h ∆V = (πhø) ∆ø + πø² ∆h
4 2 4
V1 = [pic 69](7.7*10-3) 2(219*10-3) ∆V1 = [pic 70](219*10-3)(7.7*10-3)(0.1*10-3) +[pic 71](7.7*10-3) 2 (0.1*10-2)
V1 = [m3] ∆V1 = 0.01*10-5 [m3] [pic 72]
V2 = [pic 73](7.7*10-3) 2 (228*10-3) ∆V2 = [pic 74](228*10-3)( 7.7*10-3)(0.1*10-3) + [pic 75](7.7*10-3) 2 (0.1*10-2)
V2 = [m3] ∆V2 = 0.01*10-5 [m3] [pic 76]
V3 = [pic 77](7.7*10-3) 2 (236*10-3) ∆V3 = [pic 78](236*10-3)( 7.7*10-3)(0.1*10-3) + [pic 79](7.7*10-3) 2 (0.1*10-2)
V3 = [m3] ∆V3 = 0.01*10-5 [m3] [pic 80]
V4 = [pic 81](7.7*10-3) 2 (243*10-3) ∆V4 = [pic 82](243*10-3)(7.7*10-3)(0.1*10-3) + [pic 83](7.7*10-3) 2 (0.1*10-2)
V4 = [m3] ∆V4 = 0.01*10-5 [m3] [pic 84]
V5 = [pic 85](7.7*10-3) 2 (249*10-3) ∆V5 = [pic 86](249*10-3)(7.7*10-3)(0.1*10-3) + [pic 87](7.7*10-3) 2 (0.1*10-2)
V5 = [m3] ∆V5 = 0.01*10-5 [m3] [pic 88]
V6 = [pic 89](7.7*10-3) 2 (254*10-3) ∆V6 = [pic 90](254*10-3)(7.7*10-3)(0.1*10-3) + [pic 91](7.7*10-3) 2 (0.1*10-2)
V6 = [m3] ∆V6 = 0.01*10-5 [m3] [pic 92]
V7 = [pic 93](7.7*10-3) 2 (261*10-3) ∆V7 = [pic 94](261*10-3)(7.7*10-3)(0.1*10-3) + [pic 95](7.7*10-3) 2 (0.1*10-2)
V7 = [m3] ∆V7 = 0.01*10-5 [m3] [pic 96]
V8 = [pic 97](7.7*10-3) 2 (267*10-3) ∆V8 = [pic 98](267*10-3)(7.7*10-3)(0.1*10-3) + [pic 99](7.7*10-3) 2 (0.1*10-2)
V8 = [m3] ∆V8 = 0.01*10-5 [m3] [pic 100]
V´ = 1/V[pic 101] ∆V´= ∆V/ V 2
V1´ = 1/V1 ∆V1´= ∆V1 /(V1) 2
V1´ = 1/(*10-5) ∆V1´= (0.01*10-5)/ *10-5) 2[pic 102][pic 103]
V1´ [1/m3] ∆V1´= 0.01*105 [1/m3][pic 104]
V2´ = 1/V2 ∆V2´= ∆V2 /(V2) 2
V2´ = 1/(*10-5) ∆V2´= (0.01*10-5)/ (*10-5) 2[pic 105][pic 106]
V2´ = [1/m3] ∆V2´= 0.01*105 [1/m3][pic 107]
V3´ = 1/V3 ∆V3´= ∆V3 /(V3) 2
V3´ = 1/(*10-5) ∆V3´= (0.01*10-5)/ (*10-5) 2[pic 108][pic 109]
V3´ [1/m3] ∆V3´= 0.01*105 [1/m3][pic 110]
V4´ = 1/V4 ∆V4´= ∆V4 /(V4) 2
V4´ = 1/(*10-5) ∆V4´= (0.01*10-5)/ *10-5) 2[pic 111][pic 112]
V4´ = [1/m3] ∆V4´= 0.01*105 [1/m3][pic 113]
V5´ = 1/V5 ∆V5´= ∆V5 /(V5) 2
V5´ = 1/(*10-5) ∆V5´= (0.01*10-5)/ (*10-5) 2[pic 114][pic 115]
V5´ = [1/m3] ∆V5´= 0.01*105 [1/m3][pic 116]
V6´ = 1/V6 ∆V6´= ∆V6 /(V6) 2
V6´ = 1/(*10-5) ∆V6´= (0.01*10-5)/ (*10-5) 2[pic 117][pic 118]
V6´ = [1/m3] ∆V6´= 0.01*105 [1/m3][pic 119]
V7´ = 1/V7 ∆V7´= ∆V7 /(V7) 2
V7´ = 1/(*10-5) ∆V7´= (0.01*10-5)/ (*10-5) 2[pic 120][pic 121]
V7´ = [1/m3] ∆V7´= 0.01*105 [1/m3][pic 122]
V8´ = 1/V8 ∆V8´= ∆V8 /(V8) 2
V8´ = 1/(*10-5) ∆V8´= (0.01*10-5)/ *10-5) 2[pic 123][pic 124]
V8´ = [1/m3] ∆V8´= 0.01*105 [1/m3][pic 125]
CÁLCULO PARA LA PRESIÓN
Pgas = P0 – ρhg g H ∆Pgas = ∆P0 + gH∆ρhg + ρhgH∆g + ρhg g∆H
P1 gas = P0 – ρhg g H1
P1 gas = (1.01*105) – (13.55*103)(9.81)(17*10-3)
P1 gas = [N/m2] [pic 126]
∆P1 gas = ∆P0 + gH1∆ρhg + ρhgH1∆g + ρhg g∆H1
∆P1 gas = (0.01*105) + (9.81) (17*10-3 )(0.01*103) + (13.55*103) (17*10-3 )(0.01) + (13.55*103)*(9.81)*(0.02*10-2)
∆P1 gas = 0.01*104 [N/m2]
P2 gas = P0 – ρhg g H2
P2 gas = (1.01*105) – (13.55*103)(9.81)( 22*10-3)
P2 gas = [N/m2] [pic 127]
∆P2 gas = ∆P0 + gH2∆ρhg + ρhgH2∆g + ρhg g∆H2
∆P2 gas = (0.01*105) + (9.81( 22*10-3) (0.01*103) + (13.55*103)*( 22*10-3)*(0.01) + (13.55*103)*(9.81)*(0.02*10-2)
∆P2 gas = 0.01*104 [N/m2]
P3 gas = P0 – ρhg g H3
P3 gas = (1.01*105) – (13.55*103)(9.81)( 28*10-3)
P3 gas = [N/m2] [pic 128]
∆P3 gas = ∆P0 + gH3∆ρhg + ρhgH3∆g + ρhg g∆H3
∆P3 gas = (0.01*105) + (9.81*28*10-3)(0.01*103) + (13.55*103)*( 28*10-3)*(0.01) + (13.55*103)*(9.81)*(0.02*10-2)
∆P3 gas = 0.01*104 [N/m2]
P4 gas = P0 – ρhg g H4
P4 gas = (1.01*105) – (13.55*103)(9.81)( 42*10-3)
P4 gas = [N/m2] [pic 129]
∆P4 gas = ∆P0 + gH4∆ρhg + ρhgH4∆g + ρhg g∆H4
∆P4 gas = (0.01*105) + (9.81*42*10-3)(0.01*103) + (13.55*103)*( 42*10-3)*(0.01)
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