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Ley de Boyle. Es una de las leyes de los gases ideales

Enviado por   •  4 de Febrero de 2018  •  1.989 Palabras (8 Páginas)  •  562 Visitas

Página 1 de 8

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CÁLCULO PARA EL VOLUMEN

Ø = (7.7 ± 0.1) X 10-3 m

V = πø² h ∆V = (πhø) ∆ø + πø² ∆h

4 2 4

V1 = [pic 69](7.7*10-3) 2(219*10-3) ∆V1 = [pic 70](219*10-3)(7.7*10-3)(0.1*10-3) +[pic 71](7.7*10-3) 2 (0.1*10-2)

V1 = [m3] ∆V1 = 0.01*10-5 [m3] [pic 72]

V2 = [pic 73](7.7*10-3) 2 (228*10-3) ∆V2 = [pic 74](228*10-3)( 7.7*10-3)(0.1*10-3) + [pic 75](7.7*10-3) 2 (0.1*10-2)

V2 = [m3] ∆V2 = 0.01*10-5 [m3] [pic 76]

V3 = [pic 77](7.7*10-3) 2 (236*10-3) ∆V3 = [pic 78](236*10-3)( 7.7*10-3)(0.1*10-3) + [pic 79](7.7*10-3) 2 (0.1*10-2)

V3 = [m3] ∆V3 = 0.01*10-5 [m3] [pic 80]

V4 = [pic 81](7.7*10-3) 2 (243*10-3) ∆V4 = [pic 82](243*10-3)(7.7*10-3)(0.1*10-3) + [pic 83](7.7*10-3) 2 (0.1*10-2)

V4 = [m3] ∆V4 = 0.01*10-5 [m3] [pic 84]

V5 = [pic 85](7.7*10-3) 2 (249*10-3) ∆V5 = [pic 86](249*10-3)(7.7*10-3)(0.1*10-3) + [pic 87](7.7*10-3) 2 (0.1*10-2)

V5 = [m3] ∆V5 = 0.01*10-5 [m3] [pic 88]

V6 = [pic 89](7.7*10-3) 2 (254*10-3) ∆V6 = [pic 90](254*10-3)(7.7*10-3)(0.1*10-3) + [pic 91](7.7*10-3) 2 (0.1*10-2)

V6 = [m3] ∆V6 = 0.01*10-5 [m3] [pic 92]

V7 = [pic 93](7.7*10-3) 2 (261*10-3) ∆V7 = [pic 94](261*10-3)(7.7*10-3)(0.1*10-3) + [pic 95](7.7*10-3) 2 (0.1*10-2)

V7 = [m3] ∆V7 = 0.01*10-5 [m3] [pic 96]

V8 = [pic 97](7.7*10-3) 2 (267*10-3) ∆V8 = [pic 98](267*10-3)(7.7*10-3)(0.1*10-3) + [pic 99](7.7*10-3) 2 (0.1*10-2)

V8 = [m3] ∆V8 = 0.01*10-5 [m3] [pic 100]

V´ = 1/V[pic 101] ∆V´= ∆V/ V 2

V1´ = 1/V1 ∆V1´= ∆V1 /(V1) 2

V1´ = 1/(*10-5) ∆V1´= (0.01*10-5)/ *10-5) 2[pic 102][pic 103]

V1´ [1/m3] ∆V1´= 0.01*105 [1/m3][pic 104]

V2´ = 1/V2 ∆V2´= ∆V2 /(V2) 2

V2´ = 1/(*10-5) ∆V2´= (0.01*10-5)/ (*10-5) 2[pic 105][pic 106]

V2´ = [1/m3] ∆V2´= 0.01*105 [1/m3][pic 107]

V3´ = 1/V3 ∆V3´= ∆V3 /(V3) 2

V3´ = 1/(*10-5) ∆V3´= (0.01*10-5)/ (*10-5) 2[pic 108][pic 109]

V3´ [1/m3] ∆V3´= 0.01*105 [1/m3][pic 110]

V4´ = 1/V4 ∆V4´= ∆V4 /(V4) 2

V4´ = 1/(*10-5) ∆V4´= (0.01*10-5)/ *10-5) 2[pic 111][pic 112]

V4´ = [1/m3] ∆V4´= 0.01*105 [1/m3][pic 113]

V5´ = 1/V5 ∆V5´= ∆V5 /(V5) 2

V5´ = 1/(*10-5) ∆V5´= (0.01*10-5)/ (*10-5) 2[pic 114][pic 115]

V5´ = [1/m3] ∆V5´= 0.01*105 [1/m3][pic 116]

V6´ = 1/V6 ∆V6´= ∆V6 /(V6) 2

V6´ = 1/(*10-5) ∆V6´= (0.01*10-5)/ (*10-5) 2[pic 117][pic 118]

V6´ = [1/m3] ∆V6´= 0.01*105 [1/m3][pic 119]

V7´ = 1/V7 ∆V7´= ∆V7 /(V7) 2

V7´ = 1/(*10-5) ∆V7´= (0.01*10-5)/ (*10-5) 2[pic 120][pic 121]

V7´ = [1/m3] ∆V7´= 0.01*105 [1/m3][pic 122]

V8´ = 1/V8 ∆V8´= ∆V8 /(V8) 2

V8´ = 1/(*10-5) ∆V8´= (0.01*10-5)/ *10-5) 2[pic 123][pic 124]

V8´ = [1/m3] ∆V8´= 0.01*105 [1/m3][pic 125]

CÁLCULO PARA LA PRESIÓN

Pgas = P0 – ρhg g H ∆Pgas = ∆P0 + gH∆ρhg + ρhgH∆g + ρhg g∆H

P1 gas = P0 – ρhg g H1

P1 gas = (1.01*105) – (13.55*103)(9.81)(17*10-3)

P1 gas = [N/m2] [pic 126]

∆P1 gas = ∆P0 + gH1∆ρhg + ρhgH1∆g + ρhg g∆H1

∆P1 gas = (0.01*105) + (9.81) (17*10-3 )(0.01*103) + (13.55*103) (17*10-3 )(0.01) + (13.55*103)*(9.81)*(0.02*10-2)

∆P1 gas = 0.01*104 [N/m2]

P2 gas = P0 – ρhg g H2

P2 gas = (1.01*105) – (13.55*103)(9.81)( 22*10-3)

P2 gas = [N/m2] [pic 127]

∆P2 gas = ∆P0 + gH2∆ρhg + ρhgH2∆g + ρhg g∆H2

∆P2 gas = (0.01*105) + (9.81( 22*10-3) (0.01*103) + (13.55*103)*( 22*10-3)*(0.01) + (13.55*103)*(9.81)*(0.02*10-2)

∆P2 gas = 0.01*104 [N/m2]

P3 gas = P0 – ρhg g H3

P3 gas = (1.01*105) – (13.55*103)(9.81)( 28*10-3)

P3 gas = [N/m2] [pic 128]

∆P3 gas = ∆P0 + gH3∆ρhg + ρhgH3∆g + ρhg g∆H3

∆P3 gas = (0.01*105) + (9.81*28*10-3)(0.01*103) + (13.55*103)*( 28*10-3)*(0.01) + (13.55*103)*(9.81)*(0.02*10-2)

∆P3 gas = 0.01*104 [N/m2]

P4 gas = P0 – ρhg g H4

P4 gas = (1.01*105) – (13.55*103)(9.81)( 42*10-3)

P4 gas = [N/m2] [pic 129]

∆P4 gas = ∆P0 + gH4∆ρhg + ρhgH4∆g + ρhg g∆H4

∆P4 gas = (0.01*105) + (9.81*42*10-3)(0.01*103) + (13.55*103)*( 42*10-3)*(0.01)

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