Calculo
Enviado por rodolfo faasch • 12 de Diciembre de 2022 • Tareas • 400 Palabras (2 Páginas) • 158 Visitas
[pic 1]
Universidad Tecnologica Centro Americana Calculo I
Tarea 4
Rodolfo Enrique Faasch Herrera 21741126
Ing. Gustavo Adolfo Bustillo 8/12/2018
33. 𝑦 = 𝑥3+7 = 𝑦′ = 𝑥2 + 7𝑥−1 = 𝑦′ = 2𝑥 − 7𝑥2[pic 2]
𝑥
(𝜃−1)(𝜃2+𝜃+1) 𝜃3 1
34. 𝑟 = = −[pic 3][pic 4][pic 5]
= 1 − 𝜃−3 = 𝑟′ = 3𝜃−4 = 𝑟′′ =
−12𝜃−5
𝜃3
𝜃3
𝜃3
35. 𝑦 =
𝑡2+5𝑡−1 =
𝑡2[pic 6]
(𝑡2+5𝑡−1)(2𝑡)−(𝑡2+5)(𝑡2) =
𝑡4[pic 7]
(𝑡2+5𝑡−1)(2)−(𝑡2+5)(𝑡) =
𝑡3[pic 8]
𝑦′ = − 5𝑡−2 = 𝑦′′ = − −10𝑡+6[pic 9][pic 10]
𝑡3 𝑡4
𝑞2+3 𝑞4−1 𝑞2 3
𝑞4 1 1
36. 𝑝 = ( 12𝑞 ) (12𝑞3 ) = (12𝑞 + 12𝑞) (12𝑞3 − 12𝑞3) = (12 𝑞 −[pic 11][pic 12][pic 13][pic 14][pic 15][pic 16][pic 17]
1 𝑞−1) (𝑞 − 𝑞3)[pic 18]
4
= 𝑝′
= 1 𝑞 −
6[pic 19]
1 𝑞
6[pic 20]
−3 + 𝑞−5
= 𝑝′′
= 1 −
6[pic 21]
1 𝑞
4[pic 22]
−4 + 5𝑞−6
37. 𝑤 = (𝑥2+𝑥)(𝑥2−𝑥+1) = 𝑥(𝑥3+1) = 𝑥3+1 = 1 + 𝑥−3 = 𝑤′ = −3𝑥−4 =[pic 23][pic 24][pic 25]
𝑤′′ = 12𝑥−5
𝑥4
𝑥4
𝑥3
38. 𝑤 = ( 1+3𝑧) (3 − 𝑧) = 1+3𝑧 ∗ (3 − 𝑧) = (1+3𝑧)(3−𝑧) =[pic 26][pic 27][pic 28]
3𝑧
3𝑧
3𝑧
9𝑧−3𝑧−1−3𝑧 = 3𝑧−1 = 𝑤′ = 1 − 3𝑧−1 = 𝑤′′ = 3𝑧−2[pic 29][pic 30]
3𝑧 3𝑧
...