Algebra Lineal MATRICES Y DETERMINANTES
Enviado por monto2435 • 14 de Octubre de 2018 • 678 Palabras (3 Páginas) • 489 Visitas
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C22= (2)+(4)= [pic 112][pic 113][pic 114]
A=[pic 115]
EJERCICIO
Sumar el cuadrado de una matriz y su inversa y determinar o hallar
+ [pic 116][pic 117]
= [pic 118][pic 119]
C11=(1)(1)+(-5)(3)=1-15=-14
C12=(1)(-5)+(-5)(-1)=-5+5=0
C21=(3)(1)+(-1)(3)=3-3=0
C22=(3)(5)+(-1)(-1)=-15+1=-14
= [pic 120][pic 121][pic 122]
F2-3F1=F2
3-3(1)=3-3=0
-1-3(-5)=-1+15=14
0-3(1)=0-3=-3
1-3(0)=1-0=1
= [pic 123][pic 124][pic 125]
-14F1-5F2=F1
-14(1)-5(0)=-14-0=-14
-14(-5)-5(14)=70 -70=0
-14(1)-5(-3)=-14+15=1
-14(0)-5(1)=-0 -5=-5
= [pic 126][pic 127][pic 128]
A= [pic 129]
I2 [pic 130]
+ [pic 131][pic 132]
+ [pic 133][pic 134][pic 135]
COFACTORES
A== A’= [pic 136][pic 137][pic 138]
A== (3)(4)-(2)(1)=12-2=10[pic 140][pic 141][pic 139]
-? 2x2= orden[pic 142]
= = = [pic 143][pic 144][pic 145][pic 146][pic 147]
A== (1)(-1)-(-5)(3)= -1+15=14[pic 148]
= = [pic 149][pic 150][pic 151]
INVERSA DE LA MATRIZ
SISTEMA DE 3X3 POR METODO DE GAUS
EJERCICIO 1
[pic 152]
Celdas: 31, 21, 32, 13, 23, 12
2F3+ F1= F3
2(-1)+(2)= -2+2=0
2(0)+(1)= 0+1=1
2(1)+(-2)= 2-2=0
2(0)+(1)= 0+1=1
2(0)+(0)= 0+0=0
2(1)+(0)= 2+0=2
[pic 153]
-2F2+ F1= F2
-2(1)+(2)= -2+2=0
-2(1)+(1)= -2+1= -1
-2(-2)+(-2)= 4-2=2
-2(0)+(1)= 0+1=1
-2(1)+(0)= -2+0= -2
-2(0)+(1)= 0+0=0
[pic 154]
F3+ F2= F3
0+(0)=0+0=0
1+(-1)=1-1=0
0+(2)=0+2=2
1+(1)=1+1=2
0+(-2)=0-2= -2
2+(0)=2+0=2
[pic 155]
F1+ F3= F1
2+(0)=2+0=2
1+(0)=1+0=1
-2+(2)=-2+2=0
1+(2)=1+2=3
0+(-2)=0-2= -2
0+(2)=0+2=2
[pic 156]
F2- F3= F2
0-0=0
-1-0= -1
2-2=0
1-2= -1
-2+2=0
0-2=-2
[pic 157]
F1+ F2= F1
2+0=2
1+(-1)=0
0+0=0
3+(-1)=2
-2+0=-2
2+(-2)=0
÷
÷ [pic 158][pic 159]
[pic 160]
[pic 161][pic 162]
2(1)+ 1(1)+(-2)(1)=1
2(-1)+1(0)+(-2)(-1)=0
2(0)+1(2)+(-2)(1)=0
1(1)+1(1)+(-2)(1)=0
1(-1)+1(0)+(-2)(-1)=1
1(0)+1(2)+(-2)(1)=0
-1(1)+0(1)+1(1)=0
-1(-1)+0(0)+1(-1)=0
-1(0)+0(2)+1(1)=1
[pic 163]
EJERCICIO 2 TERMINAR
A1= [pic 164]
C=31, 21, 32, 13, 23, 12
3F3+F1=F3
3(-1)+3=0
3(2)+2=8
3(1)+5=8
3(0)+1=1
3(0)+0=0
3(1)+0=3
A2=[pic 165]
3F2-2F1=F2
3(2)-2(3)=0
3(-1)-2(2)=-7
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